Question

The height h(t) in feet of a basket ball in t seconds is given by the equation h(t)=-16t^2+96t+3.At what time is the basketball 147ft above the ground?

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Answer 1

Answer:

At t = 3 the ball will reach the height of 147 ft from the ground

Step-by-step explanation:

h(t) = -16t^2 +96t +3

》 Since h(t) is the height (in feet) of basket ball from ground in t seconds

》Therefore h(t) = 147 ft

147 = -16t^2 +96t +3

16t^2 - 96t + 144 = 0

》Using factorization method

Diveding both the sides by 16

t^2 - 6t + 9 = 0

t^2 - 3t - 3t + 9 = 0

t(t-3) - 3(t-3) = 0

(t-3)(t-3) = 0

t = 3