The height h(t) in feet of a basket ball in t seconds is given by the equation h(t)=-16t^2+96t+3.At what time is the basketball 147ft above the ground?
Answers
Answered by
1
Answer:
At t = 3 the ball will reach the height of 147 ft from the ground
Step-by-step explanation:
h(t) = -16t^2 +96t +3
》 Since h(t) is the height (in feet) of basket ball from ground in t seconds
》Therefore h(t) = 147 ft
147 = -16t^2 +96t +3
16t^2 - 96t + 144 = 0
》Using factorization method
Diveding both the sides by 16
t^2 - 6t + 9 = 0
t^2 - 3t - 3t + 9 = 0
t(t-3) - 3(t-3) = 0
(t-3)(t-3) = 0
t = 3
Similar questions