Question

The height of a ball t seconds after it’s thrown into the air from the top of a building can be modeled by h(t) = –16t² + 48t + 64, where h(t) is height in feet. After how many seconds does the ball hit the ground?( class 10)​

Answer 1

Answer!


When the ball hits the ground h will be = 0

h(t) = -16t^2 + 64t + 80
0 = h(t) = -16t^2 + 64t + 80 Solve for 't' using Quadratic Formula
One answer provided by the Quad Form will be -1 ......you want the POSITIVE answer for 't'



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