the height of a ball thrown into air with the initial velocity of 24ft/s from a height of 6 feet above the ground is given by the equation h= -16t^2+24t+6 where t is the time (in seconds) , that the ball has been in the air . after how many seconds is the ball at a height of 14 feet
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answer is in attachment
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Look at the page above for your answer.
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