Question

the height of a child during swinging where is above the Ground from 0.5 metre at the lowest point 2.0m.at the highest point.the max; speed of the child is

Answer 1

Answer:

Given:

Minimum height = 0.75 m

Maximum height = 2 m

To Find:

Maximum swinging speed =?

Solution:

When the child goes up the energy stored is the potential energy, there the kinetic energy will be zero.

When the child comes down then the potential energy is been converted into kinetic energy.

Drop in “potential energy” = maximum kinetic energy

m g(2-0.75)=\frac{1}{2} m v^{2}

v=\sqrt{2g(1.25)}

v=\sqrt{(2)\times(9.8)\times(1.25)}