Question

The height of a conc is 24cm and the
diameter of its base
its base is 14cm, Find it
slant height and total surface area​

Answer 1

Question given :

• The height of a cone is 24cm and the diameter of its base is 14cm, Find its slant height and total surface area

Given parameters :

• Height of the Cone is 24 cm
• The diameter of the cone is 14 cm

To find :

• The slant height
• The total surface area

Formulas used :

• Slant height = √r² + h²
• Total surface area of cone = πrl + πr²

Required solution :

If the diameter is 14 cm then the radius would be ,

Diameter / 2 that is 7 cm

Let's now find the slant height ,

• $\sf\:\sqrt{7^2\:+\:{24}^2}$
• $\sf\:\sqrt{49\:+\:576}$
• $\sf\:\sqrt{625}$
• $\sf\:25$

Now It's the time to find the total surface area ,

• Area = πrl + πr²

• $\sf\:\dfrac{22}{7}\:\times\:7\:\times\:25\:+\:\dfrac{22}{7}\:\times\:7^2$

• 22 × 25 + 22 × 7

• 22 ( 25 + 7 )

• 22 × 32

• Area = 704 cm²

Answer 2

Correct question :

The height of a cone is 24cm and the diameter of its base is 14cm, Find its slant height and total surface area

Given Perimeters :

Heights

Cone - 24 cm

Diameter of cone - 14 cm

We have to find

• The slant height of diameter
• The total surface area

Formula used in this question is :

Slant height = √r² + h²

Total surface area of cone = πrl + πr²

Solution of the question is :

If the diameter is 14 cm then the radius would be ,

Diameter / 2 that is 7 cm

Let's now find the slant height ,

$\sqrt{7 {}^{2} + 24 {}^{2} }$

$\sqrt{49 + 576}$

$\sqrt{625}$

= 25

Find the total surface area ,

$Area = πrl + πr²$

$\frac{22}{7} \times 7 \times 25 + \frac{22}{7} \times 7 {}^{2}$

22 × 25 + 22 × 7

22 ( 25 + 7 )

22 × 32

Area = 704 cm²