Question

The height of a cone is 16 cm and its base radius is 12 cm. Find CSA and TSA of the cone. (use pie = 3.14)​

Answer 1

Answer:-

★ Given:-

• h = 16cm

• r = 12cm

Here,

▪︎h = Height

▪︎ r = radius

▪︎l = slant Height

▪︎CSA = Curved Surface Area

▪︎TSA = Total Surface Area

★ To Find:-

• CSA of cone

• TSA of cone

★ Formula Used:-

• l² = h² + r²

• CSA of cone = πrl

• TSA of cone = πrl + πr²

★ Solution:-

➢ Finding slant height of cone

As we know

l² = h² + r²

By putting the given values,

l² = 16² + 12²

➟ l² = 256 + 144

➟ l² = 400

➟ l = √400

➟ l = √20 × 20

∴ l = slant height = 20cm

➢ Finding CSA of cone

CSA of cone = πrl

Putting the given values;

CSA

= 3.14 × 12 × 20

= 3.14 × 240

= 753.6 cm²

∴ CSA of cone is 753.6 cm²

➢ Finding TSA of cone

TSA of cone = πrl + πr²

Putting the given values;

TSA

= CSA + (3.14 × 12²)

= 753.6 + (3.14 × 144)

= 753.6 + 452.16

= 1205.76 cm²

∴ TSA of cone is 1205.76 cm²

Answer 2

Question:

The height of a cone is 16 cm and its base radius is 12 cm. Find CSA and TSA of the cone. (use pie = 3.14).

We are given wíth:

● h ( height) = 16cm

● r ( radius) = 12cm

we have to fínd :

■ CSA ( curved surface Area)

■ TSA ( Total surface area)

■ and also have to find 'l' = slant height.

Slant height of the cone :

using formula:

$➪l {}^{2} = \sqrt{h {}^{2} + r {}^{2} }$

$l {}^{2} = \sqrt{16 {}^{2} + 12 {}^{2} }$

$l {}^{2} = \sqrt{400}$

$l = 20cm$

CSA of cone:

using formula

$➪\pi \: rl$

$= 3.14 \times 12 \times 20$

$= 3.14 \times 240$

$= 753.6cm {}^{2}$

Therefore Curved surface Area is 753.6cm²

TSA of cone:

using formula

$➪\pi \: rl + \pi \: r {}^{2}$

Here, for

$\pi \: rl \:$

we use the CSA of cone".

putting values:

$= 753.6 +( 3.14 \times 12 {}^{2} )$

$= 753.6 + (3.14 \times 144)$

$= 753.6 + 452.16$

$= 1205.76cm {}^{2}$

Therefore Total surface Area is 1205.76cm²

$\sf\red{hope\:it\:helps\:you}$