Question

the height of a cone is 4 cm and slant height 5 cm find the volume of cone​

Answer 1

$\sf \Large Solution!!$

We can assume the Height of cone as the Height of a Right angled Triangle whose base = Radius of the cone and slant height represents the Hypotenuse of that Triangle such that we can apply Pythagoras Theorem.

$\sf \to 4^{2}+r^{2}=5^{2}$

$\sf \to 16+r^{2}=25$

$\sf \to r^{2}=9$

$\sf \to r=\sqrt{9}$

$\sf \to r=3$

$\sf \large Now,$

$\sf \to Volume\:of\:cone=\dfrac{1}{3}\pi r^{2}h$

$\sf \to Volume\:of\:cone=\dfrac{1}{3}\times \dfrac{22}{7}\times (3\:cm)^{2}\times 4\:cm$

$\sf \to Volume\:of\:cone=\dfrac{1}{3}\times \dfrac{22}{7}\times 9\:cm^{2}\times 4\:cm$

$\sf \to Volume\:of\:cone=\dfrac{264}{7}cm^{3}$

$\sf \boxed{\bigstar Volume\:of\:cone=37.71\:cm^{3}}$

Thanks for asking!! :)

Answer 2

Answer:

• Answer:37.71 cm^3

Answer:37.71 cm^3Step-by-step explanation:

• Answer:37.71 cm^3Step-by-step explanation:Slant height (l) = 5 cm
• Answer:37.71 cm^3Step-by-step explanation:Slant height (l) = 5 cmHeight (h)= 4 cm
• Answer:37.71 cm^3Step-by-step explanation:Slant height (l) = 5 cmHeight (h)= 4 cmRadius(r)= ?

• r^2= 5^2 - 4^2
• r^2= 25 -16
• r^2= 9
• r=
• $\sqrt{9}$
• r= 3cm
• Volume of cone = 1/3
• $\pi \: r ^{2} h$
• 1/3 × 22/7 × 3×3 × 4
• Now simplify above equation.
• 264/7= 37.71 cm^3 Answer.