the height of a cone whose slant height 26cm and the diameter of the base is 10cm is
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Answer:
h =
Step-by-step explanation:
[tex] \sqrt{l { }^ {2} } - x {}^{2} = h[/tex
h= root l square -r square
h = root 26 square -10 square
h= root of 956 -100
h=root of 26 square -10 square
(root square cancle )
h =26 - 10
h= 16
therefore h= 16
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