Math, asked by SUBHIKSHA2006, 8 months ago

the height of a cone whose slant height 26cm and the diameter of the base is 10cm is ​

Answers

Answered by supritakki
1

Answer:

h =

Step-by-step explanation:

[tex] \sqrt{l { }^ {2} } - x {}^{2} = h[/tex

h= root l square -r square

h = root 26 square -10 square

h= root of 956 -100

h=root of 26 square -10 square

(root square cancle )

h =26 - 10

h= 16

therefore h= 16

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