Question

The height of a cylinder is 14 cm and its curved surface area is 704 sq.
cm, then its diameter is​

Answer 1

Answer:

h= 14 cm

c s a = 704 sq cm

Step-by-step explanation:

C S A =2 πrh

704 =2 × 22/ 7× r × 14

r = 704 × 7

2× 22× 14

= 8

radius= 8 cm

diameter = 2r = 8× 2

= 16 cm

Answer 2

Given:-

• Height of a cylinder is 14 cm.
• Curved surface area of the Cylinder is 704 cm².

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To find:-

• Diameter of the cylinder.

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Solution:-

★Formula used:-

${\dag}\:{\underline{\boxed{\sf{\purple{Curved\: surface\: area_{(cylinder)} = 2 \pi rh}}}}}$

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$\tt\longmapsto{704 = 2 \times \dfrac{22}{7} \times r \times 14}$

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$\tt\longmapsto{704 = 2 \times 22 \times r \times 2}$

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$\tt\longmapsto{704 = 44 \times 2 \times r}$

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$\tt\longmapsto{704 = 88 \times r}$

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$\tt\longmapsto{r = \dfrac{704}{88}}$

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$\tt\longmapsto{\boxed{\orange{r = 8\: cm}}}$

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Therefore,

• Radius (r) = 8 cm
• Diameter (d) = 8 × 2 = 16 cm

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Hence,

• the diameter of the cylinder is 16 cm.

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★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

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$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

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$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

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$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

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$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

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$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

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$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$