the height of a cylinder is double of its diameter and its volume is 539 cu.cm What is the diameter of its base in cm?
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Let diameter of cylinder be x cm
Radius = x/2 cm
Height of cylinder (h) = 2 x cm
Area of base (a) =pi × (x/2)² cm² = 22/7 ×x²/4 cm²
Volume of cylinder (V) = a × h = 539 cm³
So, 22x²/28 × 2x =539
or, x³ = 539 ×7 /11 =49× 7
So, x = (7³)^⅓ =7 cm
So, diameter of base = 7 cm (ans).
.
Hope this is ur required answer.
Hope I helped u.
Radius = x/2 cm
Height of cylinder (h) = 2 x cm
Area of base (a) =pi × (x/2)² cm² = 22/7 ×x²/4 cm²
Volume of cylinder (V) = a × h = 539 cm³
So, 22x²/28 × 2x =539
or, x³ = 539 ×7 /11 =49× 7
So, x = (7³)^⅓ =7 cm
So, diameter of base = 7 cm (ans).
.
Hope this is ur required answer.
Hope I helped u.
rakeshmohata:
welcome... dear
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