Question

The height of a multistorey building is 190 m and the depth of its basement
is 10 m. A lift in building moves at a rate of 10 m/ 15 second. If a man
starts from terrace, how long will it take him to reach at bottom of the
basement ?
​

Answer 1

Answer:

300 sec

Step-by-step explanation:

Total distance the man has to travel (s) = 190 + 10 = 200 m

Speed of lift (v) = $\frac{10}{15}=\frac{2}{3}m/s$

Times taken,

$t=\frac{distance}{speed} = \frac{200}{\frac{2}{3} } = \frac{600}{2} = 300 s$

=300 sec

Answer 2

Answer:

300sec

Step-by-step explanation:

As total distance = 190+10=200m

And speed = 10m/15sec

Time taken from top to bottom of the building is

1min = 40m

200m =5 min or 300sec

Hope it helps

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