Question

The height of a multistorey building is 190 m and the depth of its basement
s 10 m. A lift in building moves at a rate of 10 m/ 15 second. If a man
starts from terrace, how long will it take him to reach at bottom of the
basement ?​

Answer 1

Answer:

300 sec

Step-by-step explanation:

Total distance the man has to travel (s) = 190 + 10 = 200 m

Speed of lift (v) = \frac{10}{15}=\frac{2}{3}m/s

15

10

=

3

2

m/s

Times taken,

\begin{gathered}t=\frac{distance}{speed} = \frac{200}{\frac{2}{3} } = \frac{600}{2} = 300 s\\\end{gathered}

t=

speed

distance

=

3

2

200

=

2

600

=300s

=300 sec

Answer 2

Answer:

• Q.Here Is Your Answer •

• A multi storey building has 35 floors above the ground level each of height 7.5 m. It also has 3 floors in the basement each of height 5 m. A lift in building moves at a rate of 1 m/s. If a man starts from 50 m above the ground, how long will it take him to reach at 3rd floor of basement? A. 40 sec B. 65 sec C. 68 sec D. 32 sec

Explanation:

I hope it's help you :)