Question

The height of a parallelogram having an area of 36 cm² and base 9 cm is:​

Answer 1

hope this answer be helpful !!!!!♥️

Answer 2

AnswEr-:

• $\underline {\mathrm { The \: Height \:of \:Parallelogram \:is\:\bf{\pink{9cm}}}}$

Explanation-:

• $\mathrm{\bf{\blue {Given \:\: -:}}} \begin{cases} \sf{\blue{The\:Area \:of\:the\: Parallelogram \:\: \:is\:= \frak{36\:cm^{2}}}} & \\\\ \sf{\red{Base \:of\: Parallelogram \:is \:=\:\frak{9cm}}}\end{cases}$

• $\mathrm{\bf{\blue {To\:Find\: -:}}} \begin{cases} \sf{\pink{The\:Height \:of\:the\: Parallelogram }}\end{cases}$

$\dag{\mathrm {\bf{ Solution \:of\:Question \:-:}}}$

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• $\underline{\boxed{\star{\sf{\red{Area\:of \:Parallelogram \:-:Height \times Base \: sq.units }}}}}$

• $\mathrm{\bf{\blue {Here \:\: -:}}} \begin{cases} \sf{\blue{The\:Area \:of\:the\: Parallelogram \:\: \:is\:= \frak{36\:cm^{2}}}} & \\\\ \sf{\red{Base \:of\: Parallelogram \:is \:=\:\frak{9cm}}}& \\\\ \sf{\pink{ Height \:of\: Parallelogram \:is \:=\:\frak{??}}}\end{cases}$

Now by putting known Values in the Formula for Area of Parallelogram-:

• $:\longmapsto {\sf{ 36cm^{2} = 9 \times Height }}$

• $:\longmapsto {\sf{ \dfrac{36}{9} = Height }}$

• $:\longmapsto {\sf{ \dfrac{\cancel {36}}{\cancel {9}} = Height }}$

• $\underline{\boxed {\sf{ 4\:cm = Height }}}$

Hence ,

• $\underline {\mathrm { The \: Height \:of \:Parallelogram \:is\:\bf{\pink{9cm}}}}$

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$\large{\dag{\mathrm {\bf {Solution \:of\:Question \:-:}}}}$

• $\underline{\boxed{\star{\sf{\red{Area\:of \:Parallelogram \:-:Height \times Base \: sq.units }}}}}$
• $\mathrm{\bf{\blue {Here \:\: -:}}} \begin{cases} \sf{\blue{The\:Area \:of\:the\: Parallelogram \:\: \:is\:= \frak{36\:cm^{2}}}} & \\\\ \sf{\red{Base \:of\: Parallelogram \:is \:=\:\frak{9cm}}}& \\\\ \sf{\pink{ Height \:of\: Parallelogram \:is \:=\:\frak{4cm}}}\end{cases}$

Now by putting known Values in the Formula for Area of Parallelogram-:

• $:\longmapsto {\sf{ 36cm^{2} = 9 \times 4 }}$

• $:\longmapsto {\sf{ 36cm^{2} = 36cm^{2} }}$

Therefore,

• $:\longmapsto {\sf{ LHS = RHS }}$

• $:\longmapsto {\sf{ Hence,\: Verified\:! }}$

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