Math, asked by SahilKv, 11 months ago

The height of a parallelogram is one-third of its base. If the area of the parallelogram is 108cm². Find the base and the height.

Answers

Answered by Munajir
2

Answer:

base * height = area of paralleologram

X* 1÷3x = 108

x² = ✓324

X= 18

now base = 18 cm

height = 18÷3 = 6 cm

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Answered by anjali30703
9

Answer:

Base of parallelogram = x = 18 cm

And

Height of parallelogram = x/3 = 6cm

Step-by-step explanation:

Given,

The height of a parallelogram is one-third of its base.

Area of the parallelogram is 108cm².

Let the base of parallelogram be x .

Then,

Height of parallelogram = 1/3 rd of base of parallelogram

Height of parallelogram = x/3 .

According to the question

Area of parallelogram = 108 cm²

Base × Height = 108 cm²

x × x/3 = 108 cm²

x²/3 = 108 cm²

x² = 3 × 108 cm²

x² = 324 cm²

x = √324 cm²

x = 18 cm

x/3 = 18/3 cm = 6cm

Base of parallelogram = x = 18 cm

And

Height of parallelogram = x/3 = 6cm

Hence,

Base of parallelogram = x = 18 cm

Base of parallelogram = x = 18 cmAnd

Base of parallelogram = x = 18 cmAndHeight of parallelogram = x/3 = 6cm

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