The height of a parallelogram is one third of its base. If the area of the parallelogram is 192cm2, find its height and base.
Answers
Given :
Area of parallelogram = 192cm²
The height of a parallelogram is one-third of its base
So,
Let the base be x cm.
Height = 1/3x cm.
Area of Parallelogram = Base × Height
Base × Height = 192
x × 1/3x = 192
1/3 x² = 192
x² = 192 × 3
x² = 576
x = √576
x = 24cm
•Base = x = 24cm.
Height = 1/3x = 1/3 × 24
•Height = 8 cm
Therefore, the base and height of parallelogram respectively 24cm & 8cm.
Given :
- The height of a parallelogram is one third of its base.
- The area of the parallelogram is 192 cm².
To find
- It's height and base =?
Step-by-step explanation :
Let, the base of the parallelogram be, x.
It is Given that :
The height of a parallelogram is one third of its base.
So, Height of parallelogram = x × 1/3 = x/3.
We know that,
Area of Parallelogram = Base × Height
Substituting the values in the above formula, we get,
➮ 192 = x × x/3 [Cross Multiplication]
➮ x × x = 192 × 3
➮ x² = 576
➮ x = 24
Therefore, We got the value of, x = 24.
Hence,
Base of the parallelogram, x = 24 cm.
Height of the Parallelogram, x/3 = 24/3 = 8 cm