Question

The height of a parallelogram is one third of its base. If the area of the parallelogram is 192cm2, find its height and base.

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Answer 1

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Given :

Area of parallelogram = 192cm²

The height of a parallelogram is one-third of its base

So,

Let the base be x cm.

Height = 1/3x cm.

Area of Parallelogram = Base × Height

Base × Height = 192

x × 1/3x = 192

1/3 x² = 192

x² = 192 × 3

x² = 576

x = √576

x = 24cm

•Base = x = 24cm.

Height = 1/3x = 1/3 × 24

•Height = 8 cm

Therefore, the base and height of parallelogram respectively 24cm & 8cm.

Answer 2

Given :

• The height of a parallelogram is one third of its base.

• The area of the parallelogram is 192 cm².

To find

• It's height and base =?

Step-by-step explanation :

Let, the base of the parallelogram be, x.

It is Given that :

The height of a parallelogram is one third of its base.

So, Height of parallelogram = x × 1/3 = x/3.

We know that,

Area of Parallelogram = Base × Height

Substituting the values in the above formula, we get,

➮ 192 = x × x/3 [Cross Multiplication]

➮ x × x = 192 × 3

➮ x² = 576

➮ x = 24

Therefore, We got the value of, x = 24.

Hence,

Base of the parallelogram, x = 24 cm.

Height of the Parallelogram, x/3 = 24/3 = 8 cm