Question

the height of a parallelogram is one third of its base if the area of parallelogram is 512cm2 find the base and height​

Answer 1

Step-by-step explanation:

Let the length of its base be x

The height is

3

1

x

The area of base is given by

=base×height

=x×

3

1

x

=

3

x

2

Which is equal to 192

⟹

3

1

x

2

=192

x

2

=576

x=24

So the base is 24 cm

And the height is

3

24

=8 cm

Answer 2

Answer:

${ \huge{ \underline{ \bf{ \red{Given}}}}}$

Area of parallelogram = 512 cm²

Height of parallelogram is one third of its base.

${ \tt{let \: take \: base \: as \: x}}$

${ \tt{so \: height \: = \frac{1}{3} x}}$

Find :-

Base and Height

Solution:-

Area of parallelogram = base × Height

${ \tt{512 = x \times \frac{1}{3}x }}$

${ \tt{512 = x \times \frac{x}{3} }}$

${ \tt{512 = \frac{ {x}^{2} }{3} }}$

${ \tt{ {x}^{2} = 512 \times 3 }}$

${ \tt{ {x}^{2} = 1536 }}$

${ \tt{x = \sqrt{1536} }}$

${ \tt{x = 39.19}}$

So, Base = 39.19

Height = 1/3×39.19= 13.06

Step-by-step explanation:

Verification:-

Area of parallelogram = b×h

512 = 39.19 × 13.06

512 = 511.82

512=512

Hence proved✔