Question

the height of a parallelogram is one- third of its base. if the area of the parallelogram is 108cm² , find its base and height​

Answer 1

Step-by-step explanation:

Let the base be -x

Then height-x/3

Area of llgm – 108cmsquare

b×h = 108cmsquare

X*x/3= 108

Xsquare= 108*3

X=√324

Base of parallelogram – 18cm

Height of the parallelogram – x/3

=18/3

= 6cm.

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Answer 2

Given:-

• Area of the parallelogram = 108 cm²

To Find:-

Base and height of the parallelogram

Assumption:-

Let the base be x

Height = $\sf{\dfrac{1x}{3}}$

Solution:-

We know,

Area of parallelogram = Base × Height sq.units

Therefore,

$\sf{108 = x \times \dfrac{1x}{3}}$

= $\sf{108\times 3 = x^2}$

= $\sf{x^2 = 324}$

= $\sf{x = \sqrt{324}}$

= $\sf{x = 18\:cm}$

Now,

$\sf{Length = x = 18 \:cm}$

Breadth = $\sf{\dfrac{1x}{3} = \dfrac{18\times1}{3} = 6\:cm}$

Verification:-

Area of the parallelogram must be 108 cm²

= $\sf{Length\times Breadth\:\:sq.units}$

= $\sf{18\times6\:cm^2}$

= $\sf{108\:\:cm^2}$ [Hence Verified]

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Formula Used:-

Area of parallelogram = $\sf{L\times B\:\:sq.units}$

Where,

L = Length

B = Breadth

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About Parallelogram:-

• Parallelogram is a shape with two pairs of equal sides.

• Permeter of a parallelogram = 2(sum of the lengths of the adjacent sides) units.

• Number of vertices in a Parallelogram is 4

• Number of edges of a Parallelogram is 4.

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