the height of a parallelogram is one third of its base if the area of the parallelogram is 192 cm square find its height and base
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Answered by
6
let the height of parallelogram be h cm and base be b cm
according to the ques
h = 1/3b
area of parallelogram= b×h
b×h = 192
b×1/3b=192
b^2=576
b=24cm
h=1/3b. (given)
h=24/3
h=8cm
hope it helps
plz mark it as the brainliest
according to the ques
h = 1/3b
area of parallelogram= b×h
b×h = 192
b×1/3b=192
b^2=576
b=24cm
h=1/3b. (given)
h=24/3
h=8cm
hope it helps
plz mark it as the brainliest
Answered by
9
Answer:
Step-by-step explanation:
Given
Area of parallelogram = 192cm²
The height of a parallelogram is one-third of its base
So
Let the base be x cm.
Height = 1/3x cm.
Area of Parallelogram = Base X Height
Base × Height = 192
x × 1/3x = 192
= 1/3 x2 = 192
= x2 = 192 × 3
= x2 = 576
x = √576
x = 24cm
Base = x = 24cm.
And Height = 1/3x = 1/3 × 24
= Height = 8 cm
Base= 24cm and height = 8cm
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