Question

THE HEIGHT OF A PARALLELOGRAM IS ONE THIRD OF ITS BASE.IF THE PARALLELOGRAM IS 192 CM SQUARE .FIND ITS HEIGHT AND BASE

Answer 1

★★★Hey friend!!!★★★

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→ Let the base of the parallelogram be b, so that the height becomes (b/3), so we have

√ b*(b/3) = 192, or

√ b^2 = 192 multiply 3 = 576, or

√ b = 576^0.5 = 24.

√ So the base is 24 cm and the distance between the opposite sides in 8 cm.

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★★★i hope this may help u!!★★★

Answer 2

Step-by-step explanation:

$\huge \sf{ÃÑẞWÈR}$

❥let, base=xcm

$\sf {Height = \frac{1}{3} x \: cm}$

$\fbox \red{area \: of \: paralellogram = base ×height}$

$\sf {192 {}^{2} = x \times \frac{x}{3} }$

$\sf {192 {}^{2} = \frac{x {}^{2} }{3} }$

$\sf{x {}^{2} = 576}$

$\sf{x = 24}$

$\sf{↪base = 24cm}$

$\sf{height = \frac{x}{3} = \frac{24}{3}}$

$\mathscr{↪height = 8cm}$

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