The height of a parallelogram is one third of its base.If the parallelogram is 192cm square. Find its height and base
Answers
Answered by
9
Let the Base be a
Height = a/3
Area = a × a /3
=> 192 = a^2 / 3
=> a^2 = 576
=> a = 24
Base = 24 cm
Height = 24 /3 = 8 cm
Height = a/3
Area = a × a /3
=> 192 = a^2 / 3
=> a^2 = 576
=> a = 24
Base = 24 cm
Height = 24 /3 = 8 cm
Answered by
7
hiii!!!
here's ur answer...
ATQ,
the height of the parallelogram is one third of its base.
let the base of the parallelogram be x.
therefore height of the parallelogram is 1/3 of x.
= x/3
area of the parallelogram = 192cm²
==> b × h = 192cm²
==> x × x/3 = 192cm²
==> x²/3 = 192cm²
==> x² = 192 × 3
==> x² = 576
==> x = √576
==> x = 24
hence, base of the parallelogram = x
= 24cm
height of the parallelogram = 1/3 of x
= 1/3 × 24
= 8cm
VERIFICATION :-
area of the parallelogram = b ×
= 24 × 8
= 192cm²
hence verified
hope this helps..!!
here's ur answer...
ATQ,
the height of the parallelogram is one third of its base.
let the base of the parallelogram be x.
therefore height of the parallelogram is 1/3 of x.
= x/3
area of the parallelogram = 192cm²
==> b × h = 192cm²
==> x × x/3 = 192cm²
==> x²/3 = 192cm²
==> x² = 192 × 3
==> x² = 576
==> x = √576
==> x = 24
hence, base of the parallelogram = x
= 24cm
height of the parallelogram = 1/3 of x
= 1/3 × 24
= 8cm
VERIFICATION :-
area of the parallelogram = b ×
= 24 × 8
= 192cm²
hence verified
hope this helps..!!
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