Question

the height of a parallelogram is one third of its base if the area of parallelogram is 192 find the height and base

Answer 1

let the height and base of the parallelogram be h and b respectively.

Here ATQ,
h = (1/3)b
=> 3h = b
area = 192 cm²

We know area = h x b
=> 192 = 3b x b
=> 3h² = 192
=> h² = 64
=> h = √64
=> h = 8 cm

Thus b = 3h
=> b = 24 cm

Hope this helps

Answer 2

Let the base (B) of the parllelogram be x
Height (H) of parallelogram = base/3 = x/3
Area (A) of parallelogram = 192

A = B*H
192 = x*(x/3)

192*3 = x^2
x= Sq root(576) = 24

Base = x = 24
Height = x/3 = 24/3 = 8