Math, asked by jasijaskm3381, 1 year ago

The height of a parallelogram is one third of its base if the area of the paralleligram is 192cm2find its base and base?

Answers

Answered by Ommani
2
Let the base of the parallelogram be x cm.

Now, from the above information we conclude that the height if the parallelogram = x/3 cm.

A to Q

Area of Parallelogram = Base * Height

=> 192 = x * x/3

=> x^2 = 192*3

=> x^2 = 576

=> x = √576

=> x = 24 cm

Hence, Base of a Parallelogram = 24 cm

And, Height of a Parallelogram = 24/3 = 8 cm...

Hope it helps.....
Answered by vishakha201
2
hey here is ur ans
as we know....
area of parallelogram is a product of its base nd height
area=b*h
let base be x
then height will be1/3 of x
x*1/3x=192 cm^2
1/3x^2=192
x^2=192÷3
x^2=64
x=square root of 64
x=8


from the equation
base=8 cm
height=1/3 of base
=1/3*8=8/3 cm
hope it helps nd mark me as brainlist
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