The height of a parallelogram is one third of its base if the area of the paralleligram is 192cm2find its base and base?
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Answered by
2
Let the base of the parallelogram be x cm.
Now, from the above information we conclude that the height if the parallelogram = x/3 cm.
A to Q
Area of Parallelogram = Base * Height
=> 192 = x * x/3
=> x^2 = 192*3
=> x^2 = 576
=> x = √576
=> x = 24 cm
Hence, Base of a Parallelogram = 24 cm
And, Height of a Parallelogram = 24/3 = 8 cm...
Hope it helps.....
Now, from the above information we conclude that the height if the parallelogram = x/3 cm.
A to Q
Area of Parallelogram = Base * Height
=> 192 = x * x/3
=> x^2 = 192*3
=> x^2 = 576
=> x = √576
=> x = 24 cm
Hence, Base of a Parallelogram = 24 cm
And, Height of a Parallelogram = 24/3 = 8 cm...
Hope it helps.....
Answered by
2
hey here is ur ans
as we know....
area of parallelogram is a product of its base nd height
area=b*h
let base be x
then height will be1/3 of x
x*1/3x=192 cm^2
1/3x^2=192
x^2=192÷3
x^2=64
x=square root of 64
x=8
from the equation
base=8 cm
height=1/3 of base
=1/3*8=8/3 cm
hope it helps nd mark me as brainlist
as we know....
area of parallelogram is a product of its base nd height
area=b*h
let base be x
then height will be1/3 of x
x*1/3x=192 cm^2
1/3x^2=192
x^2=192÷3
x^2=64
x=square root of 64
x=8
from the equation
base=8 cm
height=1/3 of base
=1/3*8=8/3 cm
hope it helps nd mark me as brainlist
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