Question

the height of a parallelogram is one third of its base. if the area is 108sq​

Answer 1

Answer:

base=6

height=2

Step-by-step explanation:

let the base of a parallelogram is x

height of parallelogram = ⅓ of x = ⅓ × x

Area of parallelogram = b × h = 108

x ×⅓ × x = 108

x × x = 108 ÷ ⅓

√x² = √36

x = 6

so,base of parallelogram = 6

height of Parallelogram = ⅓ of 6 = ⅓ × 6 = 2