Question

the height of a parallelogram is one third of its base if the area of the parallelogram is 108
square cm find the length of its base and altitude

Answer 1

let base of parallelogram be x
thus, height =1/3x
area of parallelogram= base × height
108=(x) (x/3)
108=x²/3
108×3=x²
324=x²
x²=324
x=√324
x=18 cm
thus, base (x) =18 cm
altitude =x/3=18/3=6 cm
PLS MAKE MY ANSWER BRAINLIEST
FOLLOW ME IF I HELPED YOU

Answer 2

Here is your answer-

let,
Area of the llgm = 108sq.cm
base = x
height ( altitude ) of llgm = 1/3x __(1)

Area of llgm = base × height

108 = x × 1/3x

108 = 1/3x^2

324 = x^2 ( multiplied by 3 )

x^2 - 324 = 0

x^2 + 0x - 324 = 0

( x - 18 ) ( x + 18 ) = 0 ( By factorization)

x - 18 = 0 or. x + 18 = 0

x = 18 or x = -18

length is never negative.

Therefore, x = 18

Put x = 18 in (1)
= 1/3 × 18
= 6cm

Base of llgm = 18cm
Height of llgm = 6cm

Verify:-

Area of llgm = base × height
108 = 18 × 6
108 = 108

Hope it helps you...!!!!
Pls Mark it as a Brainlist.....