the height of a parallelogram is one third of its base if the area of the parallelogram is 108 square centimetres find the length of its base and altitude
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let base of parallelogram be x
thus, height =1/3x
area of parallelogram= base × height
108=(x) (x/3)
108=x²/3
108×3=x²
324=x²
x²=324
x=√324
x=18 cm
thus, base (x) =18 cm
altitude =x/3=18/3=6 cm
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thus, height =1/3x
area of parallelogram= base × height
108=(x) (x/3)
108=x²/3
108×3=x²
324=x²
x²=324
x=√324
x=18 cm
thus, base (x) =18 cm
altitude =x/3=18/3=6 cm
PLS MAKE MY ANSWER BRAINLIEST
FOLLOW ME IF I HELPED YOU
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