Question

The height of a rectangular stock room 6m and perimeter of its floor is 50 m. Find the
outer area of the four walls to be painted.​

Answer 1

outer area of the four walls to be painted. = 300 m² , if Height of room = 6 m & perimeter of Floor = 50 m

Step-by-step explanation:

Let say length & Breadth of room are L & B  m

Height of room H = 6 m

Area of four Walls = L * H  + B * H  + L * H  + B * H

= 2 *(L + B)  * H

2 *(L + B) = Perimeter of floor = 50

= 50 * 6

= 300 m²

outer area of the four walls to be painted. = 300 m²

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Answer 2

Answer:

height=6m, perimeter of floor=50=2(l+b)

area of 4 walls =l×h+b×h+l×h+b×h=2lh+2bh=2(l+b)h

=50×6=300m^2

outer area of four walls painted=300m^2