the height of a right circular cylinder is 10.5 cm.if three times the sum of the areas of its two circular faces is twice the area of the curved surface area.find the radius of its base.
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Answered by
44
Height of cylinder = 10.5 cm
Let radius of cylinder = r cm
So,
Area of two bases of cylinder = 2πr2
Area of curved surface of cylinder = 2πrh
Now,
=
=3(2πr2) =2( 2πrh)
= 6πr2=4πrh
= 3r=2 x 10.5 cm
r=2x 10.5 /3 =7cm
Radius of base of cylinder = 7 cm
Let radius of cylinder = r cm
So,
Area of two bases of cylinder = 2πr2
Area of curved surface of cylinder = 2πrh
Now,
=
=3(2πr2) =2( 2πrh)
= 6πr2=4πrh
= 3r=2 x 10.5 cm
r=2x 10.5 /3 =7cm
Radius of base of cylinder = 7 cm
Akanksha1111115:
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Answered by
14
h=10.5cm
sum of the areas of two circular area =2πr^2
BY THE GIVEN CONDITION,
3(2πr^2)=2(2πrh)
6πr^2=4πrh
(dividing both sides throughout by 2π we get)
3r^2=2rh
3×r×r=2×r×h
(Now ,dividing both sides by r)
3r=2h
3r=2(10.5)
3r=21
r=21/3
r=7cm
THEREFORE,
THE RADIUS OF THE RIGHT
CIRCULAR CYLINDER IS 7cm
HOPE THIS HELPS!!!
sum of the areas of two circular area =2πr^2
BY THE GIVEN CONDITION,
3(2πr^2)=2(2πrh)
6πr^2=4πrh
(dividing both sides throughout by 2π we get)
3r^2=2rh
3×r×r=2×r×h
(Now ,dividing both sides by r)
3r=2h
3r=2(10.5)
3r=21
r=21/3
r=7cm
THEREFORE,
THE RADIUS OF THE RIGHT
CIRCULAR CYLINDER IS 7cm
HOPE THIS HELPS!!!
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