the height of a right circular cylinder is 10.5 CM. if three times the sum of the areas of its two circular face is twice the area of curved surface area. find the radius of its base
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Answer:
7 cm
Step-by-step explanation:
Let the radius of its base be 'r' cm.
Given, height of a right circular cylinder (h) = 10.5 cm.
Given 'three times the sum of areas of its Circular face is twice the CSA'.
⇒ 3(πr² + πr²) = 2 * 2πrh
⇒ 3(2πr²) = 4πrh
⇒ 6πr² = 4πrh
⇒ 6r = 4h
⇒ 6r = 4 * 10.5
⇒ 6r = 42
⇒ r = 7 cm.
Therefore, the radius of its base = 7 cm.
Hope it helps!
fley00:
thanks a lot....
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