The height of a right circular cylinder is 10.5 m. Three times the sum of the areas of its two circular faces is twice the area of the curved surface. Find the volume of the cylinder.
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ANS: Given: height of cylinder = 10.5
According to the question,
3(2 πr2) = 2(2πrh) [since three times the sum of the areas of its two circular faces is twice the area of the curved surface area]
=> 6πr2 = 4πrh
=> 6πr2 / 4πr = h
=> 3r/2 = 10.5 [since h = 10.5]
=> r = 2*10.5/3 = 7cm
Therefore, the radius of the base is 7cm.
According to the question,
3(2 πr2) = 2(2πrh) [since three times the sum of the areas of its two circular faces is twice the area of the curved surface area]
=> 6πr2 = 4πrh
=> 6πr2 / 4πr = h
=> 3r/2 = 10.5 [since h = 10.5]
=> r = 2*10.5/3 = 7cm
Therefore, the radius of the base is 7cm.
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Answer is in the picture check it.
The answer is 7 cm check in the picture.
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