Question

The height of a right circular cylinder is 12.6 cm. three times the sum of he areas of it's two circular faces is twice the area of curved surface . Find the volume of the cylinder​

Answer 1

Answer:

Step-by-step explanation:

HEIGHT=12.6 CM

FROM THE QUESTION,3(SUM OF AREAS OF TWO OF ITS CIRCLES)=2(2*pi*r*h)

3(2*pi*r*r)=2(2*pi*r*h)

6*r=4*h

6*r=4*12.6

r=2*4.2

r=8.4cm

volume=pi*r*r*h

=22\7*8.4*8.4*12.6

=105.84*26.4

=279.4176 cm^3

hope this is helpful....

Answer 2

The volume of cylinder is 2794.176 cubic cm.

Step-by-step explanation:

We are given the following in the question:

Height of  right circular cylinder = 12.6 cm

According to question:

$3(\text{Area of two circular disc})=2(\text{Curved surface area})$

Area of circular disc =

$\pi r^2$

Curved surface are =

$2\pi rh$

where r is the radius of the cylinder and h is the height.

Putting values, we get,

$3(\pi r^2 + \pi r^2) = 2(2\pi r (12.6))\\6\pi r^2 = 4\pi r(12.6)\\\\r = \dfrac{4\times 12.6}{6} = 8.4~cm$

Volume of cylinder =

$V = \pi r^2 h\\\\V = \dfrac{22}{7}\times (8.4)^2(12.6) = 2794.176\text{ cubic cm}$

The volume of cylinder is 2794.176 cubic cm.

#LearnMore

A sphere of diameter 12.6 cm is melted and cast into a right circular cone of height 25.2 cm. find the diameter of the base of the cone.

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