The height of a right circular cylinder is 6cm. Three times the sum of the areas of its two circular faces is twice the area of its curved surface, Find the area of the base.
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Three times the sum of the areas of its two circulars faces is twice the area of the curved surface. Hence, The radius of the base of cylinder is 4 m.
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Let radius of base be ′r′m. Then
Let radius of base be ′r′m. Then3 ( πr² + πr²) = 2 × 2πrh
2πrh⇒ 6πr² = 4πrh
4πrh⇒ r = 4 × 6/6 = 4m
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