The height of a right circular cylinder is three times the radius of the base.If the height were four times the radius,the volume would be 1078 cc more than it was previously.Find the radius of the base.
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ATQ height is 3 times radius of the base means h=3r
volume = 3.14*r*r*h
v = 9.42r³
If height is four times the radius means h=4r
volume = 3.14*r*r*4r
v° = 12.56r³
ATQ v° = v + 1078
12.56r³ = 9.42r³ +1078
12.56r³ - 9.42r³ = 1078
3.14r³ = 1078
r³ = 1078/3.14
r³ = 343
r=∛343
r = 7
volume = 3.14*r*r*h
v = 9.42r³
If height is four times the radius means h=4r
volume = 3.14*r*r*4r
v° = 12.56r³
ATQ v° = v + 1078
12.56r³ = 9.42r³ +1078
12.56r³ - 9.42r³ = 1078
3.14r³ = 1078
r³ = 1078/3.14
r³ = 343
r=∛343
r = 7
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