The height of a tower is 10 cm . what is the length of when the sun's inclineation is 45°
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first ..the length is 10cm (A-B)
next take the length of the shadow fromed by the sun of the pole as X (B-C)
By the given information we can form a right angled triangle. ABC
which is 45° angled at C
- take at angle C
- tang 45° = AB/BC
- 1 = 10/ X
- Transpose X to tht side
- 1×X=10
- X=10cm..
- The casted shadow is 10cm..
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