Question

the height of a tower is 20m a ball is thrown up 20 m/s from the tower how long will the ball take to hit the ground

Answer 1

Answer:Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at  

2

=20(2)+0.5(−10)(2)  

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at  

2

 

45=0+0.5(10)(t  

′

)  

2

 

t  

′

=3s

Total time= 3+2= 5s

Step-by-step explanation:

Answer 2

Answer:

Naah...............