Physics, asked by arshdeepkaur03295, 5 months ago

the height of a tower is small h a ball is thrown from the tower and it covers h/2 distance when it reaches the 2nd half.what will be the finaldistance covered by the ball

Answers

Answered by farhaanaarif84
0

Answer:

A ball is dropped from the roof of a tower height =h

Total distance covered it in the last seconds of its motion

Solution

The distance covered in first 3 second

s=

2

1

at

2

=

2

1

×10×3

2

=45

If the ball takes in second to fall to ground. The distance covered in nth second

s

n

=u+

2

g

(2n−1)

=0+

2

10

(2×n−1)

=10n−5

Therefore, 45=10n−5

10n=50

n=5

Thereforeh=

2

1

=

2

1

gt

2

=

2

1

×10×25

=125m

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