the height of a tower is small h a ball is thrown from the tower and it covers h/2 distance when it reaches the 2nd half.what will be the finaldistance covered by the ball
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Answer:
A ball is dropped from the roof of a tower height =h
Total distance covered it in the last seconds of its motion
Solution
The distance covered in first 3 second
s=
2
1
at
2
=
2
1
×10×3
2
=45
If the ball takes in second to fall to ground. The distance covered in nth second
s
n
=u+
2
g
(2n−1)
=0+
2
10
(2×n−1)
=10n−5
Therefore, 45=10n−5
10n=50
n=5
Thereforeh=
2
1
=
2
1
gt
2
=
2
1
×10×25
=125m
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