Question

the height of a Trapezium whose area is 32.5 C M power 2 and base are 12 cm and 14 cm is ​

Answer 1

Given : Area of a Trapezium is 32.5 cm² and its bases are 12 cm and 14 cm .

To Find : Find the Height of the Trapezium

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SolutioN : Let's apply the foemula for Area of Trapezium to get the height . Let's Solve :

$\maltese$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ Area{\small_{(Trapezium)}} = \dfrac{1}{2} \times \bigg( a + b \bigg) \times Height }}}}}$

Where :

• a = 1st Base of Trapezium
• b = 2nd Base of Trapezium

$\maltese$ Calculating the Height of Trapezium :

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = \dfrac{1}{2} \times \bigg( a + b \bigg) \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 32.5 = \dfrac{1}{2} \times \bigg( 12 + 14 \bigg) \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 32.5 = \dfrac{1}{2} \times 26 \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 32.5 = \dfrac{26}{2} \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 32.5 = \cancel\dfrac{26}{2} \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 32.5 = 13 \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \dfrac{32.5}{13} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \dfrac{325}{130} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \cancel\dfrac{325}{130} = Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; {\underline{\boxed{\pmb{\sf{ Height = 2.5 \; cm }}}}} \; {\pink{\bigstar}} \\ \\ \\ \end{gathered}$

$\therefore \;$ Height of the Trapezium is 2.5 cm .

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Answer 2

refer the given attachment