The height of a tree is √3 times the length of its shadow Find the angle of elevation of the sun
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17
The height of a tree is root(3) ...time the length of the shadow.(given)
so let length of the shadow be h...so height is root(3)*h...
tan(angle)=height/base
tan(angle)=root(3)*h/h
tan(angle)=root(3)
therefore the angle of elevation is 60....since tan 60=root(3)....((also the sun rays are almost perpendicular to the earth...----this is assumpted))
so let length of the shadow be h...so height is root(3)*h...
tan(angle)=height/base
tan(angle)=root(3)*h/h
tan(angle)=root(3)
therefore the angle of elevation is 60....since tan 60=root(3)....((also the sun rays are almost perpendicular to the earth...----this is assumpted))
Answered by
41
given,
the height of the tree (h) AB = √3 and BC = 1
let angle c be Ф
so angle of elevation taken as tanФ
tanФ = opposite to Ф/adjacent to Ф
in ΔABC
tanФ= AB/BC
tanФ=√3/1 = √3
tanФ = √3
we know that tan 60° = √3
so ,
tanФ = √3
tanФ = tan 60°
∵ Ф = 60°
so,the angle of elevation of the sun is 60°
!hope this helpful!
the height of the tree (h) AB = √3 and BC = 1
let angle c be Ф
so angle of elevation taken as tanФ
tanФ = opposite to Ф/adjacent to Ф
in ΔABC
tanФ= AB/BC
tanФ=√3/1 = √3
tanФ = √3
we know that tan 60° = √3
so ,
tanФ = √3
tanФ = tan 60°
∵ Ф = 60°
so,the angle of elevation of the sun is 60°
!hope this helpful!
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