Question

The height of a triangle is 6 more than the base. The area is 216m^2. Find the base and the length of the triangle

Answer 1

Answer:

Step-by-step explanation:Area = (1/2)*b*h

Area = (1/2)*b*h

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2:

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2:

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to:

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to:

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm.

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm.

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm. Check:

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm. Check:Area = (1/2)bh

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm. Check:Area = (1/2)bh20 = (1/2)*10*4

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm. Check:Area = (1/2)bh20 = (1/2)*10*420 = (1/2)(40)

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm. Check:Area = (1/2)bh20 = (1/2)*10*420 = (1/2)(40)20 = 20

Area = (1/2)*b*h Where b = base and h = height. The base is 6 cm longer than the height, so b = h+6. The Area = 20 cm2: 20 = (1/2)*(h+6)*h40 = h2 + 6h0 = h2 + 6h - 40 Factors to: 0 = (h+10)(h-4)h = -10 and 4 Since we can't have a height of -10, h = 4 cm. The base is b = h+6 = 10 cm. Check:Area = (1/2)bh20 = (1/2)*10*420 = (1/2)(40)20 = 20Check!

Answer 2

Answer:

The base of ∆ is 18 m and the height is 24 m .

Step-by-step explanation:

Let the base of ∆ be x

then the height of ∆ be ( x + 6 ) m

A/q

1/2 × base × height = 216 m^2

=> 1/2 × x × ( x + 6 ) = 216

=> 1/2 ( x^2 + 6x ) = 216

=> x^2 + 6x = 432

=> x^2 + 6x - 432 = 0

=> x^2 + ( 24 - 18 ) x - 432 =0

=> x^2 + 24x - 18x - 432 = 0

=> x ( x + 24 ) - 18 ( x + 24 ) = 0

=> ( x + 24 ) ( x - 18 ) = 0

Here,

x + 24 = 0 or, x - 18 = 0

x = -24 or, x = 18

Since,

The base of ∆ can't be negative .

So,

x = 18 = base of ∆

Now,

height = x + 6

= 18 + 6

= 24

Hence,

The base of ∆ is 18 m and height is 24 m .

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