The height of a triangle is increased by 40%. What can be the maximum percentage increase in length of the base so that the increase in area is restricted to maximum of 60%?
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Answer:
14.28%
Step-by-step explanation:
Area of Triangle, A = 1/2×b×h
New Area of Triangle, A = 60% increased of A= A + 60% of A = 8A/5
New height = h + 40% of h = 7h/5
Let the new base be x.
8A/5 = 1/2 * x * 7h/5
8/5(1/2*b*h) = 1/2 * 7/5 * x * h
8b = 7x
x = 8b/7
Maximum increase in length of the base = (8b/7 -b) = b/7
Maximum percentage increase in the length of base = (b/7)/b × 100 = 1/7 × 100 = 14.28%
Hope it helps :)
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