the height of a triangle is x^4+y^4 and its base is 14xy find the area of the triangle
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base of Δ = 14 xy
hieght of Δ = x^4 +y^4
area ofΔ = 1/2×14xy ×[x^4+y^4]
7xy [x^4+y^4]
7x^5y + 7xy^5
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Proper Question : If the height of a triangle is x⁴+y⁴ and its base is 14xy find the area of the triangle ?
Answer :
Area of ∆ = 2x^5y + 2xy^5
Step - By Step Explanation :
Given :
Height of the ∆ = x⁴ + y⁴
Base of it's ∆ = 14xy
To Find : find the area of the triangle ?
Solution :
Area of ∆ = 1/ 2 × Base × Height
Area of ∆ = 1/2 × 14xy × ( x⁴ + y⁴ )
Area of ∆ = 7xy × x⁴ + y⁴
Area of ∆ = 7x^5y + 7xy^5
Answer :
Area of ∆ = 2x^5y + 2xy^5
Step - By Step Explanation :
Given :
Height of the ∆ = x⁴ + y⁴
Base of it's ∆ = 14xy
To Find : find the area of the triangle ?
Solution :
Area of ∆ = 1/ 2 × Base × Height
Area of ∆ = 1/2 × 14xy × ( x⁴ + y⁴ )
Area of ∆ = 7xy × x⁴ + y⁴
Area of ∆ = 7x^5y + 7xy^5
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