Question

The height of a triangle is x3 + y3 and its base is 14xy. Find the area of the triangle.

Answer 1

Given:-

Height of a triangle = $x^3+y^3$

Base of the triangle = 14xy

To Find:-

Area of the triangle = ?

Solution:-

Formula to find Area of the triangle

= $\dfrac{1}{2} \times base \times height$

= $\dfrac{1}{2} \times (x^3+y^3) \times 14xy$

(Divide 14 by 2.)

= $(x^3+y^3) \times 7xy$

Area of the triangle = $7x^4y + 7xy^4$

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▪Powers are added while multiplying.

▪Powers are subtracted while doing division.

Answer 2

Area of triangle = $\rightarrow\tt{ \frac{1}{2} \times height \times base}$

__________....

$\rightarrow\tt{ \frac{1}{2} \times height \times base}$

$\rightarrow \tt{ \frac{1}{ \cancel2} \times {(x}^{3} + {y}^{3}) \times {\cancel{14} {}^ { \: \: \: 7} }xy }$

$\rightarrow \tt{ {(x}^{3} + {y}^{3}) \times7 xy}$

$\rightarrow \tt \red {\boxed {\tt{7 {x}^{4}y + 7x {y}^{4} }}}$