Question

The height of a triangle is (x4 + y4) and its base is 14xy. Find the area of the triangle. (Hint: Area of the triangle = 1/2 x base x height)

Answer 1

given:
h=(x4+y4)
b=14xy

area of triangle =1/2*b*h
$= \frac{1}{2} \times ( {x}^{4} + {y}^{4} ) \times 14xy \\ = ( {x}^{4} + {y}^{4}) \times 7xy \\ = 7 {x}^{5} {y}^{} + 7x {y}^{5}$
hope it helps

Answer 2

$<b>Proper Question</b>$ : If the height of a triangle is x⁴+y⁴ and its base is 14xy find the area of the triangle ?

$<b>Answer</b>$ :

Area of ∆ = 7x⁵y+7xy⁵

$<b>Step - By Step Explanation</b>$ :

Given :

Height of the ∆ = x⁴ + y⁴

Base of it's ∆ = 14xy

$<b>To Find</b>$ : find the area of the triangle ?

$<b>Solution</b>$ :

Area of ∆ = 1/ 2 × Base × Height

Area of ∆ = 1/2 × 14xy × ( x⁴ + y⁴ )

Area of ∆ = 7xy × x⁴ + y⁴

$<b>Area of ∆ = 7x⁵ y + 7 xy⁵</b>$