Question

The height of a triangle whose base is 13cm and area is 65cm2is

Answer 1

$\bf{\underline{\underline{ \bigstar\: Figure : }}}$

$\:\:$

$\setlength{\unitlength}{1.6mm}\begin{picture}(50,20)\linethickness{0.1mm}\put(-3,-3){\line(1,1){20}}\put(-3,-3){\line(1,0){39.5}}\put(36.6,-2.8){\line(-1,1){19.8}}\put(17,-3){\line(0,1){20}}\put(18,5){height}\put(3,5){}\put(13,-5){13 cm}\end{picture}$

$\:\:$

$\bf{\underline{\underline{ \bigstar\: Given : }}}$

$\:\:$

• $\footnotesize{ Base\: of\: triangle = 13 cm }$

• $\footnotesize{ Area\: of\: triangle = {65cm}^{2} }$

$\:\:$

$\bf{\underline{\underline{ \bigstar\: To\: Find : }}}$

$\:\:$

• $\footnotesize{ Height\: of\: triangle }$

$\:\:$

$\bf{\underline{\underline{ \bigstar\: Solution : }}}$

$\:\:$

$\footnotesize{ Area\: of\: triangle = {65cm}^{2} }$

$\footnotesize{\implies \dfrac{1}{2} \times base \times height = {65cm}^{2} }$

$\footnotesize{\implies \dfrac{1}{2} \times 13cm \times height = {65cm}^{2} }$

$\footnotesize{\implies 13cm \times height = {65cm}^{2} \times 2}$

$\footnotesize{\implies 13cm \times height = {130cm}^{2} }$

$\footnotesize{\implies height = \dfrac{{130cm}^{2}} { 13cm}}$

$\footnotesize{\implies height = \cancel{\dfrac{{130cm}^{2}} { 13cm}}}$

$\footnotesize{\implies height = 10cm }$

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\:\:$

$\green{\underline \bold{Given :}}$

$\:\:$

• Base is 13 cm

• Area is 65 cm²

$\:\:$

$\red{\underline \bold{To \: Find:}}$

$\:\:$

• Height of triangle

$\:\:$

$\large{\orange{\underline{\tt{Solution :-}}}}$

$\:\:$

$\underline{\bold{\texttt{Area of triangle :}}}$

$\:\:$

$\purple\longrightarrow$ $\sf \dfrac { 1 } { 2 } \times base \times height$

$\:\:$

$\sf \longmapsto \dfrac { 1 } { 2 } \times 13 \times height = 65^2$

$\:\:$

$\sf \longmapsto 13 \times height = 130 cm^2$

$\:\:$

$\sf \longmapsto height = \dfrac { 130 } { 13 }$

$\:\:$

$\sf \longmapsto height = 10 cm$

$\:\:$

Hence height will be 10 cm

$\rule{200}5$