Question

The height of a TV tower is 235m. If the average population density
around TV tower is 1000 (KM)-2 then up to how many people can
the transmission reach ?

Answer 1

Up to 9.4 * 10⁶ people the transmission can reach if the height of the tower is 235 m to the average population density is 1000 km⁻² around T.V. tower.

Explanation:

It is given that,

The height of the T.V. tower, h = 235 m

The average population density, P  = 1000km⁻² = $\frac{1000}{1000^2}$ = 10⁻³ m⁻²

We know that,

d = √[2Rh] …… (i)

where  

h = height of the tower  

R = radius of earth = 6.4 * 10⁶ m

d = maximum distance up to which the transmission can be received

Substituting the given values in the formula (i), we get

d = $\sqrt{2 * 6.4 * 10^6 * 235}$ ……. (ii)

Thus, we have  

Population covered by the transmission is given by

= [Area of range] x [Population density]

= πd² × P

= (22/7) × (2 × 6.4 × 10⁶ × 235) × 10⁻³

= 9453.714 × 1000  

= 9.4 × 10³ × 10³

= 9.4 × 10⁶

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Also View:

A tv tower has a height of 100 m. What is the maximum distance upto which the t.V. Transmission can be received (r = 8 x 106 m)?

https://brainly.in/question/6819225

Answer 2

The transmission can reach up to 9.45 × 10⁶ people.

Explanation:

The population covered by the transmission is given by the formula:

T = (Area of range) × (Population density)

Where,

Area of range = πd²

Population density = 1000 km⁻³ = 10⁻³ m

Where,

d = √(2Rh)

Where,

R = Earth radius = 6.4 × 10⁶ m

h = Tower height = 235 m

Now,

d = √(2 × 6.4 × 10⁶ × 235) = 54.845 × 10³

Now,

T = π × (54.845 × 10³)² × 10⁻³

∴ T = 9.45 × 10⁶