the height of an equilateral triangle is 10 cm its area is
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Let the side of triangle be x...
Given it's height be h = 10 cm
Now area of equilateral triangle is
1/2 × base × h = √3/4 × x × x
1/2 × 2 × 10 = √3/4 × x × x
X = (40/√3)^1/2 cm
Which the required answer..
Hope it helps regards SR
Given it's height be h = 10 cm
Now area of equilateral triangle is
1/2 × base × h = √3/4 × x × x
1/2 × 2 × 10 = √3/4 × x × x
X = (40/√3)^1/2 cm
Which the required answer..
Hope it helps regards SR
Answered by
5
Heya User,
-->> Height of an equilateral Δ = ( √3 / 2 ) side
=> √3 / 2 * side = 10cm
=> 20√3 / 3 = side
-->> Area of equilateral Δ = √3/4 ( side )² = ( √3 / 4 )[ 400 * 3 ]/9
= 100( √3 / 3 ) cm²
^_^
-->> Height of an equilateral Δ = ( √3 / 2 ) side
=> √3 / 2 * side = 10cm
=> 20√3 / 3 = side
-->> Area of equilateral Δ = √3/4 ( side )² = ( √3 / 4 )[ 400 * 3 ]/9
= 100( √3 / 3 ) cm²
^_^
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