Question

The height of an equilateral triangle measures 9√3.find it's area

Answer 1

The formula for height of an equilateral triangle is
$height = \sqrt{3 } \div 2 \times side$
so side(a) is
$9 \sqrt{3 } = \sqrt{3} \div 2 \times a$
$9 \sqrt{3 } \times 2 \div \sqrt{3} = a$
$9 \times 2 = a$
a=18 (side =18cm)
We know area of a equilateral triangle is
$\sqrt{3 } \div 4 \times {side}^{2}$
$\sqrt{3} \div 4 \times 18 \times 18$
$\sqrt{3 } \div 4 \times 324$
$\sqrt{3} \times 81$
$104.29 {cm}^{2}$

Answer 2

Answer: 81√3cm^2

Step-by-step explanation: