Question

the height of an equilateral triangle measures 9√3. find its area​

Answer 1

Answer:

area of equilateral triangle is underoot 3/4 a²

it is an equilateral triangle

so it length and breadth are equal to height

underoot 3/4×( 9 underoot3)²

underoot 3/4× 81×3

underoot 3/4 ×243

243 underoot3/4

Answer 2

Answer:

140.3

Step-by-step explanation:

Height is 9$\sqrt{3}$ Let the equal sides of triangle be = x

By Pythagoras theorem

$x^{2}$ = $(x/2)^{2}$ + $(9\sqrt{3}) ^{2}$

$x^{2}$ - $(x/2)^{2}$  = $(9\sqrt{3}) ^{2}$

3$x^{2}$ = 81 * 3 * 4

$x^{2}$ = 81 * 3 * 4 /3

x = 18

area of equilateral triangle = $\sqrt{3}/4$ * $x^{2}$ ....Where x is the length of a side

so area = $\sqrt{3}/4$ * $18^{2}$ = 140.29612

Area = 140.3 (approx)