The height of an equilateral triangle of side 5cm is
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Answer:
4 . 3 cm
Step-by-step explanation:
At First Draw Perpendicular along Any side of ∆ ;
Then , That side will bisect into two
i.e each half measures 2.5 cm
Now , According to Pythagoras Theorem : -
( Apply on any Half of ∆ )
( Height of ∆ ) ^ 2 + ( 2.5 ) ^ 2 = ( 5 ) ^2
( Height of ∆ ) ^ 2 = 25 - 6.25 = 18.75
Therefore ; Height of ∆ = ~ 4.3 cm .
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