The height of an isoscales trapezium is equal to the difference of the parallel sides. If the
length of one of its oblique sides is 5√5 cm and the area is 140 sqcm, find the lengths of
the parallel sides.
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Answer:
we know attitude is also a median in equilateral triangle.
BG = GC = 3 cm.
from ΔABG by Pythagoras theorem.
(AB)2=(AG)2+(BG)2
(6)2=(AG)2+(3)2
(AG)=36−9
AG=27=5.20cm.
Height of trapezium = 2.60 cm → (given in question ⇒25.20=2.60cm)
Area of trapezium - 2(a+b)×h
=2(6+3)×2.60=9×1.3=11.70cm2
like this you can do this is example
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