the height of equilateral triangle is 7√3 . find its perimeter
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Answer:
as we know that the area of triangle is a1/2 ×base ×height
and the question is that its an equivalent triangle so if its height is 7√3 then it's all sides including base will be 7√3
thus, 1/2×7√3×7√3
hence (7√3)×(7√3 ) = 49×3 = 147
hence 1/2×147 = 73.5 ans
hence 73.5 m/cm ^2 Is your ans
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